Timberland Ruins #330 – Odyssey (Common)

Magic: The Gathering · Odyssey · Common

Timberland Ruins #330 Price

Timberland Ruins (#330, Common) from Odyssey is worth $0.14 to $1.74 in Near Mint condition on TCGplayer as of October 3, 2026, depending on the printing (Normal to Foil). On Cardmarket, Europe's main marketplace, the Foil sells for €1.07.

Near Mint · TCGplayer: $1.74
Near Mint · Cardmarket: €1.07
30-day change: −0.6%
Printings: 2

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Timberland Ruins prices by printing

Near Mint market prices, updated October 4, 2026.

Printing	TCGplayer (USD)	Cardmarket (EUR)
Foil	$1.74	€1.07
Normal	$0.14	€0.15

TCGplayer market price and Cardmarket price for Near Mint English copies. They are two separate markets, so the euro figure is Cardmarket's own price, not a conversion of the dollar one. Source: TCGplayer, Cardmarket.

Card details

Set: Odyssey
Card number: 330
Rarity: Common
Released: October 1, 2001
Illustrator: Alan Pollack
Type line: Land
Rules text: Timberland Ruins comes into play tapped.
T: Add G to your mana pool.
T, Sacrifice Timberland Ruins: Add one mana of any color to your mana pool.

Timberland Ruins: common questions

How much is Timberland Ruins #330 worth?

Timberland Ruins (#330, Common) from Odyssey is worth $0.14 to $1.74 in Near Mint condition on TCGplayer as of October 3, 2026, depending on the printing (Normal to Foil). On Cardmarket, Europe's main marketplace, the Foil sells for €1.07.

What set is Timberland Ruins from?

Timberland Ruins is card 330 in Odyssey, released October 1, 2001. Its rarity is Common. Illustrated by Alan Pollack.

Is Timberland Ruins going up in price?

Over the last 30 days the Near Mint Foil price on TCGplayer moved from $1.75 (September 5, 2026) to $1.74 (October 3, 2026), a change of −0.6%. The 30-day low was $1.74 and the high $1.75.

How do I check what my Timberland Ruins is worth?

Scan it with the TCG Vault app on iPhone: it identifies the card from the camera in seconds and shows its current market price and price history, then keeps it in your collection so you can follow its value.